wickedcherub: (Default)
Tina ([personal profile] wickedcherub) wrote2007-07-31 01:30 pm

haysup

Hi all,

I haven't been around much, things have been hectic and I haven't been online much at all. Harry Potter happened and damn I want to talk about that so much, then my birthday happened and I'm now officially old.

Thankyou to everyone who sent birthday wishes, I'll get back and thankyou personally when I can.

This weekend is Bloc Party weekend and I'm seeing them here on Friday then in Sydney on Saturday, and somehow squeezing in a Darren Hayes instore on the Saturday as well.

Uni's been back for two and a bit weeks and I am FLAILING because I haven't got textbooks nor am I ready and I have an assignment due in a few days that I didn't know existed that looks like this:

[a bit of backstory]
The next day, Ram receives the following message from Sandi:

ZWOZLOPGKONSVDHOUSQSYSUDXPOWVVHRDBBCIVLGSZDMVOQRWVHFHTRFHBRBHCIHKSRFLULBDZPOQIVQUWSHVVDJHGXFYWYSG


TASK:

1. Decrypt the message from Sandi giving a full description of how you did it.
(8 marks)

Hi. Welcome to SIT281: Introduction to Cryptography. O____O

It does look like a lot of fun though. I'm glad it's a compulsory subject. I just don't know where to start. Count all the letters and make the most common one 'e'?
Yeah, it's a maths subject, not a computer one, so I can't just stick it into a crypto program. It could be any sort of cipher! Looks like I'll know what I'll be doing in the queue to the Bloc Party gig. BREAKING CODE.

Uh huh.

[identity profile] knw.livejournal.com 2007-07-31 07:56 am (UTC)(link)
I think I want to do your course now.

[identity profile] wickedcherub.livejournal.com 2007-07-31 09:32 am (UTC)(link)
Err you probably don't. I spend an hour today counting and timing the oscillations of a pendulum. God it was boring.

And I really really don't know where to start with that code. They don't even tell you what sort of code it is, let alone give you the key to decrypt it. MAYBE THERE ISN'T A KEY.

[identity profile] knw.livejournal.com 2007-07-31 09:43 am (UTC)(link)
If it's just that each letter means another letter then you could start by seeing how many of each letter there are and work out which is a Q by seeing what there's least of/is always paired with another letter that might be U? But this is me having no background/reading in the area so don't laugh if that's a bad idea.